A certain basketball player can make a free throw shot 25% of the time.
Thus, p = probability of accurate free throw shot = 0.25
q = probability of incorrect free throw shot = 1-p = 0.75
To find probability that in a sequence of free throw shots this player makes his/her first shot.on the fourth try
n = 4
Thus, he misses 1st , 2nd , 3rd each with probability 0.75 and hits last one correct which has probability 0.25
Thus. required probability = P(1st fail)*P(2nd fail)*P(3rd fail)*P(4th pass)
= 0.75*0.75*0.75*0.25
= 0.1055
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