Question

# Determine the margin of error for a confidence interval to estimate the population proportion for the...

Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels with a sample proportion equal to 0.35 and n= 120

the margin of error for a confidence interval to estimate the population portion for 90% confidence level is

the margin of error for a confidence interval to estimate the population portion for 95% confidence level is

the margin of error for a confidence interval to estimate the population portion for 97% confidence level is

p = 0.35, n =120

1. Confidence interval =90%

At = 1-0.90 =0.10, critical value, zc=ABS(NORM.S,INV(0.10/2) )= 1.645

Margin of error, E =

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2. Confidence interval =95%

At = 1-0.95 =0.15, critical value, zc=ABS(NORM.S,INV(0.05/2) )= 1.96

Margin of error, E =

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3. Confidence interval =97%

At = 1-0.97 =0.03, critical value, zc=ABS(NORM.S,INV(0.03/2) )= 2.170

Margin of error, E =

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