Assume that 12 jurors are randomly selected from a population in which 76% of the people are Mexican-Americans. Refer to the probability distribution table below and find the indicated probabilities.
xx | P(x)P(x) |
---|---|
0 | 0+ |
1 | 0+ |
2 | 0+ |
3 | 0.0003 |
4 | 0.0018 |
5 | 0.0092 |
6 | 0.034 |
7 | 0.0924 |
8 | 0.1828 |
9 | 0.2573 |
10 | 0.2444 |
11 | 0.1407 |
12 | 0.0371 |
Find the probability of exactly 5 Mexican-Americans among 12
jurors. Round your answer to four decimal places.
P(x=5)=P(x=5)=
Find the probability of 5 or fewer Mexican-Americans among 12
jurors. Round your answer to four decimal places.
P(x≤5)=P(x≤5)=
Does 5 Mexican-Americans among 12 jurors suggest that the selection
process discriminates against Mexican-Americans?
probabilities.
xx | P(x)P(x) |
---|---|
0 | 0+ |
1 | 0+ |
2 | 0+ |
3 | 0.0003 |
4 | 0.0018 |
5 | 0.0092 |
6 | 0.034 |
7 | 0.0924 |
8 | 0.1828 |
9 | 0.2573 |
10 | 0.2444 |
11 | 0.1407 |
12 | 0.0371 |
Find the probability of exactly 5 Mexican-Americans among 12
jurors. Round your answer to four decimal places.
P(x=5)
Using the table
P(x=5) = 0.0092
Find the probability of 5 or fewer Mexican-Americans among 12
jurors. Round your answer to four decimal places.
P(x≤5)
P(x≤5) = P(x=0) + P(x=1) + P(x=2) + P(x=3) + P(x=4) + P(x=5)
P(x≤5) = 0 + 0 + 0 + 0.0003 + 0.0018 + 0.0092 = 0.0113
P(x≤5) = 0.0113
Does 5 Mexican-Americans among 12 jurors suggest that the selection process discriminates against Mexican-Americans?
As there is only 1% chance of having a 5 Mexican-Americans among 12 jurors, hence there is some discrimination
Yes
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