Question

Assume that when adults with smartphones are randomly selected, 54% use them in meetings or classes. If 5 adult smartphone users are randomly selected, find the probability that at least 2 of them use their smartphones in meetings or classes.

The probability is nothing. (Round to four decimal places as needed.)

Answer #1

Solution :

Given that ,

p = 0.54

1 - p = 1 - 0.54 = 0.46

n = 5

x 2

Using binomial probability formula ,

P(X = x) = ((n! / (n - x)!) * p^{x} * (1 - p)^{n -
x}

p ( x 2 ) = p (x = 2 )+ p (x = 3) + p (x = 4) + p (x = 5 )

= (5 / (5 - 2)!) * 0.54^{2} * 0.46)^{3
+}

= (5! / (5 - 3)!) * 0.54^{3} * 0.46)^{2} +

= (5 ! / (5 - 4)!) * 0.54^{4} *
0.46)^{1} +

= (5! / ( 5 - 5)!) * 0.54^{5} *
0.46)^{0} +

p ( x 2 ) = 0.8585

Probability = 0.8585

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