63% of students at one college drink coffee, and 16% of people who drink coffee suffer from insomnia. What is the probability that a randomly selected student drinks coffee and suffers from insomnia?
It is given that, yet 63% students drink coffee, 16% among those
63% percent are the one suffereing from insomnia. Supposing that
there are total n students in the college, there will be
students who drink coffee. Among 16% of the
, or
are the one who suffer insomnia.
Hence, the probability that a randomly selected student drinks
coffee and suffer from insomnia would be
or 10.08%.
Note: This solution must not be confused with or taken anlogous
to the probability rule that
, which is quite different. We must consider the problem with the
conditional probability. Supposing A is the people who drinks
coffee and hence
while B is the people who suffers from insomnia and hence
(ie probability that B given A is 0.16). Hence,
's probability would be found as
or
or
.
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