Question

Consider the following population: {7, 8, 8, 9, 9}. The value of μ is 8.2, but...

Consider the following population: {7, 8, 8, 9, 9}. The value of μ is 8.2, but suppose that this is not known to an investigator. Three possible statistics for estimating μ are

Statistic 1: the sample mean, x

Statistic 2: the sample median

Statistic 3: the average of the largest and the smallest values in the sample

A random sample of size 3 will be selected without replacement. Provided that we disregard the order in which the observations are selected, there are 10 possible samples that might result (writing 8and 8*, 9 and 9* to distinguish the two 8's and the two 9's in the population.)

7, 8, 8* 7, 8, 9 7, 8, 9* 7, 8*, 9 7, 8*, 9*
7, 9, 9* 8, 8*, 9 8, 8*, 9* 8, 9, 9* 8*, 9, 9*

(a)

For each of these 10 samples, compute Statistics 1, 2, and 3.

Statistic 1 Statistic 2 Statistic 3
7, 8, 8*
7, 8, 9
7, 8, 9*
7, 8*, 9
7, 8*, 9*
7, 9, 9*
8, 8*, 9
8, 8*, 9*
8, 9, 9*
8*, 9, 9*

(b)

Construct the sampling distribution of each of these statistics. (Enter each statistic from smallest to largest.)

Statistic 1
p(Statistic 1)
Statistic 2
p(Statistic 2)
Statistic 3
p(Statistic 3)

(c)

Which statistic would you recommend for estimating μ and why?

Using the sampling distributions above, the means of the three statistics are calculated to be E(Statistic 1) =  , E(Statistic 2) =  , and E(Statistic 3) =  . Since the mean of Statistic  ? 1 2 3 is closest to μ = 8.2, we pick the  ---Select--- sample mean sample median average of the largest and smallest values in the sample as the best of the three statistics for estimating μ.

Homework Answers

Answer #1

a)

Statistic 1 statistic 2 Statistic 3
7,8,8* 7.666667 8 7.5
7,8,9 8 8 8
7,8,9* 8 8 8
7,8*,9 8 8 8
7,8*,9* 8 8 8
7,9,9* 8.33 9 8
8,8*,9 8.33 8 8.5
8,8*,9* 8.33 8 8.5
8,9,9* 8.67 9 8.5
8*,9,9* 8.67 9 8.5

b)  

Statistic 1 7.67 8 8.33 8.67
Probability 1/10=0.1 4/10=0.4 3/10=0.3 2/10=0.2
Statistic 2 8 9
probability 7/10=0.7 3/10=0.3
Statistic 3 7.5 8 8.5
probability 1/10=0.1 5/10=0.5 4/10=0.4

c) E ( Statistic 1 ) =

= 7.67 * 0.1 + 8 * 0.4 + 8.33 * 0.3 + 8.67 * 0.2

= 8.2

E ( Statistic 2 ) =

= 8 * 0.7 + 9 * 0.3 = 8.3

E ( statistic 3 ) =

= 8.15

We have population mean =  μ = 8.2

Since the mean of Statistic 1 is closest to μ = 8.2, we pick the sample mean as the best of the three statistics for estimating μ.

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