Consider the following population: {7, 8, 8, 9, 9}. The value of μ is 8.2, but suppose that this is not known to an investigator. Three possible statistics for estimating μ are
Statistic 1: the sample mean, x
Statistic 2: the sample median
Statistic 3: the average of the largest and the smallest values in the sample
A random sample of size 3 will be selected without replacement. Provided that we disregard the order in which the observations are selected, there are 10 possible samples that might result (writing 8and 8*, 9 and 9* to distinguish the two 8's and the two 9's in the population.)
7, 8, 8* | 7, 8, 9 | 7, 8, 9* | 7, 8*, 9 | 7, 8*, 9* |
7, 9, 9* | 8, 8*, 9 | 8, 8*, 9* | 8, 9, 9* | 8*, 9, 9* |
(a)
For each of these 10 samples, compute Statistics 1, 2, and 3.
Statistic 1 | Statistic 2 | Statistic 3 | |
---|---|---|---|
7, 8, 8* | |||
7, 8, 9 | |||
7, 8, 9* | |||
7, 8*, 9 | |||
7, 8*, 9* | |||
7, 9, 9* | |||
8, 8*, 9 | |||
8, 8*, 9* | |||
8, 9, 9* | |||
8*, 9, 9* |
(b)
Construct the sampling distribution of each of these statistics. (Enter each statistic from smallest to largest.)
Statistic 1 | ||||
---|---|---|---|---|
p(Statistic 1) |
Statistic 2 | ||
---|---|---|
p(Statistic 2) |
Statistic 3 | |||
---|---|---|---|
p(Statistic 3) |
(c)
Which statistic would you recommend for estimating μ and why?
Using the sampling distributions above, the means of the three statistics are calculated to be E(Statistic 1) = , E(Statistic 2) = , and E(Statistic 3) = . Since the mean of Statistic ? 1 2 3 is closest to μ = 8.2, we pick the ---Select--- sample mean sample median average of the largest and smallest values in the sample as the best of the three statistics for estimating μ.
a)
Statistic 1 | statistic 2 | Statistic 3 | |
7,8,8* | 7.666667 | 8 | 7.5 |
7,8,9 | 8 | 8 | 8 |
7,8,9* | 8 | 8 | 8 |
7,8*,9 | 8 | 8 | 8 |
7,8*,9* | 8 | 8 | 8 |
7,9,9* | 8.33 | 9 | 8 |
8,8*,9 | 8.33 | 8 | 8.5 |
8,8*,9* | 8.33 | 8 | 8.5 |
8,9,9* | 8.67 | 9 | 8.5 |
8*,9,9* | 8.67 | 9 | 8.5 |
b)
Statistic 1 | 7.67 | 8 | 8.33 | 8.67 |
Probability | 1/10=0.1 | 4/10=0.4 | 3/10=0.3 | 2/10=0.2 |
Statistic 2 | 8 | 9 | ||
probability | 7/10=0.7 | 3/10=0.3 | ||
Statistic 3 | 7.5 | 8 | 8.5 | |
probability | 1/10=0.1 | 5/10=0.5 | 4/10=0.4 |
c) E ( Statistic 1 ) =
= 7.67 * 0.1 + 8 * 0.4 + 8.33 * 0.3 + 8.67 * 0.2
= 8.2
E ( Statistic 2 ) =
= 8 * 0.7 + 9 * 0.3 = 8.3
E ( statistic 3 ) =
= 8.15
We have population mean = μ = 8.2
Since the mean of Statistic 1 is closest to μ = 8.2, we pick the sample mean as the best of the three statistics for estimating μ.
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