Question

The population mean weight of a one-year old African Penguin is 1585 grams with a standard...

The population mean weight of a one-year old African Penguin is 1585 grams with a standard deviation of 256 grams. If 49 one year old African penguins are selected at random and weighed, what is the probability their mean weight at least 1650 grams? round your answer to three decimal places

Homework Answers

Answer #1

We will make use of the central limit theorem.

The population mean =1585, and the standard deviation =256

The random sample is of size: 49.

Let, be the random sample of weights obtained.

Then, . By the central limit theorem, the approximate distribution of is

Let, (The denominator is the standard deviation of ). Then Z~N(0,1), the standard normal distribution.

So, we want the following probability:

Now, I will make use of standard normal distribution calculator or a table to fetch the value of

This gives,

Therefore,

Thus, rounded off to 3 decimal places, is the answer.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The mean weight of King Penguins found in an Antarctic colony last year was 15.4 kg....
The mean weight of King Penguins found in an Antarctic colony last year was 15.4 kg. In a sample of 35 penguins same time this year in the same colony, the mean penguin weight is 14.6 kg. Assume the population standard deviation is 2.5 kg. The null hypothesis is that the mean penguin weight does not differ from last year. Assume the population standard deviation is 2.5 kg. If we take a sample of size 35, what is the probability...
Suppose the mean weight of King Penguins found in an Antarctic colony last year was 15.3...
Suppose the mean weight of King Penguins found in an Antarctic colony last year was 15.3 kg. In a sample of 16 penguins this year in the same colony, the mean penguin weight is 14. 3 kg. Assume the sample standard deviation is 2.7kg. Perform a hypothesis test at the α = 0.05 significance level to see if the mean weight of King Penguins has gone down this year.Use H0: μ = 15.3 Ha: μ < 15.3 a)What is the...
A particular fruit's weights are normally distributed, with a mean of 678 grams and a standard...
A particular fruit's weights are normally distributed, with a mean of 678 grams and a standard deviation of 6 grams. If you pick 18 fruit at random, what is the probability that their mean weight will be between 675 grams and 676 grams? Round answer to at least 4 decimal places.
A particular fruit's weights are normally distributed, with a mean of 225 grams and a standard...
A particular fruit's weights are normally distributed, with a mean of 225 grams and a standard deviation of 40 grams. I f you pick 16 fruit at random, what is the probability that their mean weight will be between 202 grams and 230 grams? Round answer to at least 4 decimal places. Please explain in Ti-83..
a sample of 279 one year old baby boys in the US had a mean weight...
a sample of 279 one year old baby boys in the US had a mean weight of 25.9 pounds. assume the population standard deviation is 5.9 pounds. what is the upper bound of the 90% confidence interval for the mean lifetime of the components. round your answer to two decimal places
1. The weights of 9 year old male children are normally distributed population with a mean...
1. The weights of 9 year old male children are normally distributed population with a mean of 73 pounds and a standard deviation of 12 pounds. Determine the probability that a random sample of 21 such children has an average less than 72 pounds. Round to four decimal places. 2. A normally distributed population has a mean of 80 and a standard deviation of 17. Determine the probability that a random sample of size 26 has an average greater than...
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 66 inches and standard...
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 66 inches and standard deviation 2 inches. (a) What is the probability that an 18-year-old man selected at random is between 65 and 67 inches tall? (Round your answer to four decimal places.) (b) If a random sample of fourteen 18-year-old men is selected, what is the probability that the mean height x is between 65 and 67 inches? (Round your answer to four decimal places.)
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 65 inches and standard...
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 65 inches and standard deviation 4 inches. (a) What is the probability that an 18-year-old man selected at random is between 64 and 66 inches tall? (Round your answer to four decimal places.) (b) If a random sample of eleven 18-year-old men is selected, what is the probability that the mean height x is between 64 and 66 inches? (Round your answer to four decimal places.)
Assume that the weight of marbles are normally distributed with mean 172 grams and standard deviation...
Assume that the weight of marbles are normally distributed with mean 172 grams and standard deviation 29 grams. a) If 4 marbles are selected, find the probability that its mean weight is less than 167 grams. b) If 25 marbles are selected, find the probability that they have a mean weight more than 167 grams. c) If 100 marbles are selected, find the probability that they have a mean weight between 167 grams and 180 grams.
the weight of the population of cans of coke are normally distributed with a mean of...
the weight of the population of cans of coke are normally distributed with a mean of 12 oz and a population standard deviation of 0.1 oz. A sample of 7cans is randomly selected from the popuation. (a) find the standard error of the sampling distribution. round your answer to 4 decimal places. (b) using the answer from part (a), find the probability that a sample of 7 cans will have a sample mean amount of at least 12.02 oz. Round...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT