Predictor |
Coef |
SE Coef |
T |
|||||||||||||||||||
Constant |
10.487 |
2.967 |
5.19 |
|||||||||||||||||||
X1 |
0.402 |
0.03121 |
4.20 |
|||||||||||||||||||
X2 |
-0.402 |
0.05353 |
-2.55 |
|||||||||||||||||||
X3 |
0.217 |
0.03901 |
-1.89 |
|||||||||||||||||||
X4 |
0.804 |
0.1420 |
3.97 |
|||||||||||||||||||
X5 |
-0.345 |
0.03999 |
-1.9 |
|||||||||||||||||||
Analysis of Variance |
||||||||||||||||||||||
Source |
DF |
SS |
MS |
F |
||||||||||||||||||
Regression |
5 |
3710.00 |
742.00 |
15.39 |
||||||||||||||||||
Residual Error |
47 |
2647.38 |
57.55 |
|||||||||||||||||||
Total |
52 |
6357.38 |
||||||||||||||||||||
X1 is the number of architects employed by the company. |
X2 is the number of engineers employed by the company. |
X3 is the number of years involved with health care projects. |
X4 is the number of states in which the firm operates. |
X5 is the percent of the firm's work that is health care−related |
(a) |
Write out the regression equation. (Round your answers to 3 decimal places. Negative amounts should be indicated by a minus sign.) |
(b) | How large is the sample? How many independent variables are there? |
(c-1) |
State the decision rule for .05 significance level: H0: β1 = β2 = β3 = β4 = β5 = 0; H1: Not all βi's are 0. (Round your answer to 2 decimal places.) |
(c-2) | Compute the value of the F statistic. (Round your answer to 2 decimal places.) |
(d-1) |
State the decision rule for .05 significance level. (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.) |
(d-2) |
Compute the value of the test statistic. (Round your answers to 2 decimal places. Negative amounts should be indicated by a minus sign.) |
a)The regression equation is
b) The sample size is 53. Since the total degrees of freedom is n-1=52, n=53
c) The decision rule for .05 significance level, is to reject the null hypotheis ,since F value is greater than the tabled value that is 15.89 > 2.41= F5,47
F statistic is MSR/MSE= 742/57.55 =12.89
d) Hypothesis is checking that of the individual regression coefficent is zero
The degrees of freedom is n-2 =51, then t value is 1.6752
For the variables X2,X4 and X5 the test statistic value is <1.6752, hence these variables are not significant
Thevalue of the test statistic is given in the table
Get Answers For Free
Most questions answered within 1 hours.