Question

4 couples decide separately to go out for dinner by choosing from the same list of...

4 couples decide separately to go out for dinner by choosing from the same list of 15

restaurants in a guide book. If each couple randomly chooses a restaurant from the list of 15, what is the

probability that two or more couples end up at the same restau

rant?

Math   Statistics-And-Probability   
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Answer #2

SOLUTION-

NO OF COUPLES(N) =4

PROBABILITY OF CHOOSING SAME RESTAURANT(p) = 1/15 = 0.07

LET X BE THE NO OF COUPLES THAT REACH THE SAME RESTAURANT

X ~ BINOMIAL( N=4, P=0.07)

SO,

=

=

=

=

=

****IN CASE OF DOUBT, COMMENT BELOW. ALSO LIKE THE SOLUTION, IF POSSIBLE.

answered by: anonymous
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