Question

The monthly sales"x" of a company have a mean of 25000 rupees and standard deviation of...

The monthly sales"x" of a company have a mean of 25000 rupees and standard deviation of 4000.profits "y" are calculated by multiplying sales by 0.3 and subtracting fixed cost 6000 rupees.Find the mean profit and the standard deviation of the profit.

Homework Answers

Answer #1

The monthly sales of a company is "x"

The mean of x is 25000

standard deviation of x is 4000

variance of x is 4000*4000=16000000

The profit of a company is represented by "y"

y is expressed as: y=0.3*sales-6000 = 0.3*x-6000

Mean of y= 0.3*mean(x)-6000

=0.3*25000-6000

=7500-6000 =1500

Mean of y is 1500

standard deviation of y =square root of variance of y

variance of y= (0.3)^2*variance(x)

=0.09*16000000

= 1440000

standard deviation of y is 1200

The mean of the profit is 1500 and standard deviation of profit is 1200

  

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Monthly sales have a mean of $10,000 and a standard deviation of $2,500. Profits are calculated...
Monthly sales have a mean of $10,000 and a standard deviation of $2,500. Profits are calculated by multiplying sales by 80% and subtracting fixed costs of $2,000. Find the expected monthly profit, and the standard deviation of monthly profits.
Random variable X has mean 16 and standard deviation 9, random variable Y has mean 12...
Random variable X has mean 16 and standard deviation 9, random variable Y has mean 12 and standard deviation 7, the correlation between X and Y is 0.3. How can we find the correlation between 4X - 5Y and 3Y - 1.
.x is normally distributed with a mean of 27 and a standard deviation of 9. Take...
.x is normally distributed with a mean of 27 and a standard deviation of 9. Take a random sample of n = 9 observations and imagine that you have calculated a sample mean Xbar. What is the P(Xbar < 33) )? What is the population mean , sd value and Z score ? .x is normally distributed with a mean of 27 and a standard deviation of Take a random sample of n = 9 observations and imagine that you...
For the given probability distribution, find the mean and standard deviation.    x    P(X=x)   ...
For the given probability distribution, find the mean and standard deviation.    x    P(X=x)    -1.5    0.3    0    0.5    2.75 0.1 5    0.1
Let X have a normal distribution with mean 6 and standard deviation 3 1) Compute the...
Let X have a normal distribution with mean 6 and standard deviation 3 1) Compute the probability that X>8.7 . 0-0.1 0.1-0.2 0.2-0.3 0.3-0.4 0.4-0.5 0.5-0.6 0.6-0.7 0.7-0.8 0.8-0.9 0.9-1 2) Compute the probability that X<0 . 0-0.1 0.1-0.2 0.2-0.3 0.3-0.4 0.4-0.5 0.5-0.6 0.6-0.7 0.7-0.8 0.8-0.9 0.9-1 3) Compute the probability that |X-6|>1.9 . 0-0.1 0.1-0.2 0.2-0.3 0.3-0.4 0.4-0.5 0.5-0.6 0.6-0.7 0.7-0.8 0.8-0.9 0.9-1
Find the mean and standard deviation of the random variable X with the following distribution: X...
Find the mean and standard deviation of the random variable X with the following distribution: X 0 1 2 3 4 Probability 0.1 0.2 0.3 0.3 0.1 I. 1.8, 1.29 II. 1.00, 1.00 III. 2.1, 1.135 IV. 2.1, 1.29
1. Given that the correlation between X and Y is -0.48, the mean and standard deviation...
1. Given that the correlation between X and Y is -0.48, the mean and standard deviation of X are 3.4 and 8.3, the mean and the standard deviation of Y is 6.5 and 7.2 respectively. Find the slope for the line of best fit. 2. Given that the correlation between X and Y is -0.48, the mean and standard deviation of X are 3.4 and 8.3, the mean and the standard deviation of Y is 6.5 and 7.2 respectively. Find...
question: 4.Suppose you have a distribution, X, with mean = 11 and standard deviation = 4....
question: 4.Suppose you have a distribution, X, with mean = 11 and standard deviation = 4. Define a new random variable Y = 2X - 2. Find the mean and standard deviation of Y. question 5:In testing a certain kind of missile, target accuracy is measured by the average distance X (from the target) at which the missile explodes. The distance X is measured in miles and the sampling distribution of X is given by: X 0 10 50 100...
The revenue (X) from the sales of a compay has an expected value of $7,403, with...
The revenue (X) from the sales of a compay has an expected value of $7,403, with a standard deviation of $551 while the cost (Y) has an expected value of $4,566, with a standard deviation of $348. The covariance between the revenue and cost is 1,434. What is the variance of the profit (X-Y) of the company? Hint: Answer should be accurate to 0 decimal place, i.e., an integer.
Suppose that we do not know the mean and the standard deviation, and that we have...
Suppose that we do not know the mean and the standard deviation, and that we have calculated the sample mean and that we have calculated the sample mean and sample standard deviation of the compressive strength based on 10 samples to be 6000kg/cm^2 and 100 kg/cm^2. (a) What is the probability that a sample’s strength is greater than 5800 Kg/cm2? (b) What is the probability that a sample’s strength is between 5800 Kg/cm2 and 5950 Kg/cm2? (c) What strength is...