An online site presented this question, "Would the recent norovirus outbreak deter you from taking a cruise?" Among the
34, 536
people who responded, 63%
answered "yes." Use the sample data to construct a 90%
confidence interval estimate for the proportion of the population of all people who would respond "yes" to that question. Does the confidence interval provide a good estimate of the population proportion?
__________<p< ________________
(Round to three decimal places as needed.)
We have given,
n=34,536
Estimate for sample proportion
Level of significance is =1-0.90=0.1
Z critical value(using Z table)=1.645
Confidence interval formula is
=(0.626,0.634)
Therefore,
0.626 < p < 0.634
yes, the confidence interval provide a good estimate of the population proportion.
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