Question

Hi. I need the third part of this problem, especially the second and third question. The...

Hi. I need the third part of this problem, especially the second and third question. The answer that are already in this site, are not complete. I appreciate your help. The weights of all one hundred (100) 9th graders at a school are measured, and it is found that the mean of all the measurements is 100 lbs., with a standard deviation of 15 lbs. Explain how you would use this information to determine the percentage of students who weighed between 85 lbs and 115 lbs. Make sure your explanation includes the use of z-scores. Part 2: Using the example in part 1 above, answer the following questions in the same document you used to answer the questions from part 1. Make sure you show all the work required by the questions. What is the percentage of students who weighed between 85 lbs and 115 lbs? (Show calculations) What is the z-score of a student who weighed 105 lbs? (Show calculations) If a student weighed only 60 lbs, how many students out of the one hundred 9th graders would weigh more? (Hint: calculate the percentage 1st) Part 3: The following year, the 9th grade students are weighed again, and this time it is found that the mean of all weights is 108 lbs, and the standard deviation is 17 lbs. Answer the following questions, using the same document you used in parts 1 and 2 to show how you arrived at your answers. Compare two students, one from the first class who weighed 98 lbs, and one from the second class who weighed 100 lbs. Which of the two students was heavier relative to their class? (compare z-scores) What percentage of students in the first class were heavier than the 98 lb. student? What percentage of students in the second class were heavier than the 100 lb. student?

Homework Answers

Answer #1

Part 3.

2nd question:

We can find which student was relatively heavier by comparing their respective z score.

For student from first class,

Z= 98-100/15 = -0.133

For student from second class,

z= 100-108/17 = -0.471

So since -0.133>-0.471, the student of the first class was relatively heavier

3. Percentage of students heavier than 98lb in the first class,

P(X>98) = P(Z>-0.13) = P(Z<0.13) = 0.5517 ie 55.17%

Percentage of students heavier than 100lb in second class,

P(X>100) = P(Z>-0.47) = P(Z<0.47) = 0.6808 = 68.08%

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