Question

Given the following frequency table of data, what is the potential outlier?

Value	Frequency
15	1
16	0
17	3
18	4
19	6
20	10
21	3
22	2
23	1
24	0
25	0
26	0
27	0
28	0
29	0
30	1

Select the correct answer below:

30

18

23

19

17

Answer 1

Value	Frequency	cumulative
15	1	1
16	0	1
17	3	4
18	4	8
19	6	14
20	10	24
21	3	27
22	2	29
23	1	30
24	0	30
25	0	30
26	0	30
27	0	30
28	0	30
29	0	30
30	1	31

quartile Q1 =(n+!)/4 th value =(31+1)/4 th value =8 th value =18

Q3 =3*(n+!)/4 th value =3*(31+1)/4 th value =24 th value =20

therefore lower fence limit =Q1-1.5*(Q3-Q1)=18-1.5*(20-18)=15

upper fence limit =Q3+1.5*(Q3-Q1)=20+1.5*(20-18)=23

as 30 falls outside this region

30 can be considered a potential outlier