Question

# Given the following frequency table of data, what is the potential outlier? Value Frequency 15 1...

Given the following frequency table of data, what is the potential outlier?

Value Frequency
15 1
16 0
17 3
18 4
19 6
20 10
21 3
22 2
23 1
24 0
25 0
26 0
27 0
28 0
29 0
30 1

30

18

23

19

17

 Value Frequency cumulative 15 1 1 16 0 1 17 3 4 18 4 8 19 6 14 20 10 24 21 3 27 22 2 29 23 1 30 24 0 30 25 0 30 26 0 30 27 0 30 28 0 30 29 0 30 30 1 31

quartile Q1 =(n+!)/4 th value =(31+1)/4 th value =8 th value =18

Q3 =3*(n+!)/4 th value =3*(31+1)/4 th value =24 th value =20

therefore lower fence limit =Q1-1.5*(Q3-Q1)=18-1.5*(20-18)=15

upper fence limit =Q3+1.5*(Q3-Q1)=20+1.5*(20-18)=23

as 30 falls outside this region

30 can be considered a potential outlier

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