Two dice are rolled. Assuming it is unbiased so it's 6 sided and thus the probability of getting any number on any single die is 1/6.
Now, the second die can show any number we are just concerned with rolling a 4 on the first die. So the outcomes can be this:
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6) ie we can have total 6 fabourafav outcomes. Total outcomes will be (6*6)= 36 since any of the 6 numbers can come on any dice.
Hence the required probability= total favourable outcomes/total outcomes= 6/36 ie 1/6
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