The table below contains the overall miles per gallon (MPG) of a type of vehicle. Complete parts a and b below.
33 |
24 |
31 |
34 |
28 |
29 |
20 |
33 |
33 |
29 |
43 |
32 |
33 |
22 |
a. Construct a
99% confidence interval estimate for the population mean MPG for this type of vehicle, assuming a normal distribution.The 99%
confidence interval estimate is from____MPG to ____MPG.
(Round to one decimal place as needed.)
Sample size = n = 14
Sample mean = = 30.2857
Standard deviation = s = 5.7570
We have to construct 99% confidence interval.
Formula is
Here E is a margin of error.
Degrees of freedom = n - 1 = 14 - 1 = 13
Level of significance = 0.01
tc = 3.012 ( Using t table)
So confidence interval is ( 30.2857 - 4.6347 , 30.2857 + 4.6347) = > ( 25.7 , 34.9)
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