A traffic safety company publishes reports about motorcycle fatalities and helmet use. In the first accompanying data table, the distribution shows the proportion of fatalities by location of injury for motorcycle accidents. The second data table shows the location of injury and fatalities for 2051 riders not wearing a helmet. Using the data below, complete parts (a) and (b).
Location of Injury | Probability | Frequency |
Multiple Locations | 0.57 | 1025 |
Head | 0.31 | 864 |
Neck | 0.03 | 37 |
Thorax | 0.06 | 80 |
Abdomen/Lumbar/Spine | 0.03 | 45 |
(a) Compute the expected counts for each fatal injury.
Location of injury |
Observed Count |
Expected Count |
---|---|---|
Multiple Locations |
1025 |
? |
Head |
864 |
? |
Neck |
37 |
? |
Thorax |
80 |
? |
Abdomen/Lumbar/Spine |
45 |
? |
(Round to two decimal places as needed.)
(b) What is the P-value of the test? (round to three decimal places as needed)
(a)
Location of Injury | Observed count(O) | Expected count(E) | |||
Multiple locations | 1025 | 2051*0.57 = 1169.07 | -144.07 | 20756.16 | 17.75 |
Head | 864 | 2051*0.31 = 635.81 | 228.19 | 52070.68 | 81.9 |
Neck | 37 | 2051*0.03 = 61.53 | -24.53 | 601.72 | 9.78 |
Thorax | 80 | 123.06 | -43.06 | 1854.16 | 15.07 |
Abdomen/Lumbar/Spine | 45 | 61.53 | -16.53 | 273.24 | 4.44 |
Total | 2051 | 2051 | 128.94 |
The chi square statistic = 128.94
and the degrees of freedom = (5 - 1) = 4
(b) The p value corresponding to chi-square statistic = 128.94 and df = 4 is 0.000
(From chi square table)
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