Let X equal the distribution of the possible BMIs in children with reported weight problems aged 5-18 years old. Suppose this distribution was approximately normal with mean of 21.7 and standard deviation of 1.34.
10.22 |
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23.89 |
||
None of the other choices represents a suitable response |
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1.41 |
||
23.6 |
Solution:-
Given that,
mean = = 21.7
standard deviation = = 1.34
Using standard normal table,
P(Z > z) = 8%
= 1 - P(Z < z) = 0.08
= P(Z < z) = 1 - 0.08
= P(Z < z ) = 0.92
= P(Z < 1.41) = 0.92
z = 1.41
Using z-score formula,
x = z * +
x = 1.41 * 1.34 + 21.7
x = 23.6
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