Question

**Absentee rates - Friday vs Wednesday:** We want
to test whether or not more students are absent on Friday afternoon
classes than on Wednesday afternoon classes. In a random sample of
302 students with Friday afternoon classes, 48 missed the class. In
a different random sample of 307 students with Wednesday afternoon
classes, 32 missed the class. The table below summarizes this
information. The standard error (SE) is given to save calculation
time if you are not using software.

**Data Summary**

total number | total number | Proportion | |

Day | of
absences ()x |
of
students ()n |
p̂ = (/x)
n |

Friday | 48 | 302 | 0.15894 |

Wednesday | 32 | 307 | 0.10423 |

*SE* = 0.02738

**The Test:** Test the claim that the absentee rate
on all Friday afternoon classes is greater than the absentee rate
on all Wednesday afternoon classes. Use a 0.05 significance
level.

(a) Letting *p̂*_{1} be the absentee rate from
the sample on Friday and *p̂*_{2} be the rate from
Wednesday, calculate the test statistic using software or the
formula* z* =

(p̂_{1} − p̂_{2}) −
δ_{p} |

SE |

where *δ*_{p} is the hypothesized
difference in proportions from the null hypothesis and the standard
error (*SE*) given with the data. **Round your answer
to 2 decimal places.**

*z* =

*To account for hand calculations -vs- software, your answer
must be within 0.01 of the true answer.*

(b) Use software or the z-table to get the P-value of the test
statistic. **Round to 4 decimal places.**

P-value =

Answer #1

Absentee rates - Friday vs Wednesday: We want
to test whether or not more students are absent on Friday afternoon
classes than on Wednesday afternoon classes. In a random sample of
302 students with Friday afternoon classes, 48 missed the class. In
a different random sample of 307 students with Wednesday afternoon
classes, 30 missed the class. The table below summarizes this
information. The standard error (SE) is given to save calculation
time if you are not using software.
Data...

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