Part A Suppose you’ve developed a cost estimate that has a lognormal distribution with mean $500M and coefficient of variation (CoV) of 12%.
Part B: Suppose the program office thinks your estimate is too high and has budgeted $450M for this program. Calculate the probability of a cost overrun, given your cost probability distribution.
Part C: Calculate the 75th percentile of your cost estimate.
Answer:
a)
Given,
mean = 500
Coefficient of variation = (Standard deviation/mean) * 100%
SD * 100% / mean = 12%
SD = (12*500)/100
= 6000/100
Standard deviation = 60
b)
To calculate the probability of cost overrun
i.e.,
P(X > 450) = ?
= P(ln x > ln 450)
= P( (ln X - 500)/60 > (ln(450 - 500)/60) )
= P(z > - 8.33)
= 1 - P(z <= - 8.33)
= P(z <= 8.33)
P(X > 450) = 1 (approximately)
Required probability = 1
c)
Now to calculate the 75th percentile
P(X <= x) = 75% = .75
P(ln X <= ln x) = 0.75
P(z <= ln x - 500 / 60) = 0.75
(ln x - 500) / 60 = 0.67
ln x = 0.67*60 + 500
= 40.2 + 500
ln x = 540.2
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