Does not Work in an Office | Works in an Office | Total | |
---|---|---|---|
Does not Work Saturday | 13 | 48 | 61 |
Works Saturday | 8 | 51 | 59 |
Total | 21 | 99 | 120 |
A survey of 120 employed citizens was conducted and the results are shown in the table above. Given that a randomly selected survey participant does not work in an office, what is the probability that this person works on Saturday?
P(Works Saturday/ Does not working in an office) = P(Works Saturday AND Does not working in an office)/ P(Does not working in an office)
= 8/21
So,
Answer is:
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