date |
SPY |
AAPL |
1/1/18 |
2.46% |
3.41% |
1/8/18 |
1.65% |
1.19% |
1/15/18 |
0.90% |
0.77% |
1/22/18 |
2.20% |
-3.89% |
1/29/18 |
-3.88% |
-6.42% |
date |
SPY |
AAPL |
1/1/18 |
2.46% |
3.41% |
1/8/18 |
1.65% |
1.19% |
1/15/18 |
0.90% |
0.77% |
1/22/18 |
2.20% |
-3.89% |
1/29/18 |
-3.88% |
-6.42% |
a.) SSR = 0.0031
b). se(slope) = 0.6113
c). Calculate the R2
= 0.5306
d). Test the null hypothesis that the beta is equal to 1 with a 5% significance level.
t = (1.1257-1)/0.6113
= 0.2056
DF = n-2 =3
Table value of t with 3 DF at 0.05 level =3.182
Calculated t = 0.2056 < the table value 3.182
The null hypothesis is not rejected.
There is not enough evidence to conclude that the beta is different from 1.
e). What is the approximate p-value for the test in d)?
P=0.8502
Excel Addon Megastat used.
Menu used: correlation/Regression ---- Regression Analysis.
Regression Analysis |
|||||||
r² |
0.5306 |
n |
5 |
||||
r |
0.7284 |
k |
1 |
||||
Std. Error of Estimate |
0.0319 |
Dep. Var. |
AAPL |
||||
Regression output |
confidence interval |
||||||
variables |
coefficients |
std. error |
t (df=3) |
p-value |
95% lower |
95% upper |
|
Intercept |
a = |
-0.0174 |
0.0148 |
-1.171 |
.3262 |
-0.065 |
0.030 |
SPY |
b = |
1.1257 |
0.6113 |
1.841 |
.1628 |
-0.820 |
3.071 |
ANOVA table |
|||||||
Source |
SS |
df |
MS |
F |
p-value |
||
Regression |
0.0035 |
1 |
0.0035 |
3.39 |
.1628 |
||
Residual |
0.0031 |
3 |
0.0010 |
||||
Total |
0.0065 |
4 |
|||||
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