Question

46.FOR NEXT 3 QUESTIONS USE THE FOLLOWING DIRECTION: Manager of a grocery store wants to test...

46.FOR NEXT 3 QUESTIONS USE THE FOLLOWING DIRECTION:

Manager of a grocery store wants to test to determine whether the mean waiting time of its customers is significantly more than 4 minutes. He takes a random sample of 36 customers and finds that the average length of time it took the customers in the sample to check out was 4.6 minutes. A national study estimates that standard deviation of length of time of grocery store customers is 1.8 minutes.

47.

What is the computed value of “test statistics” for this study?

a.1.96

b.1.64

c. 2.00

d. 0.056

e. None of the above

48.

The P-value of this study is

a. between 0.005 to 0.01

b. 0.01

c. 0.025

d. 0.0228

e. 0.9772

49.

At 5% level of significance, it can be concluded that the mean of the population is

a. significantly greater than 4

b. not significantly greater than 4

c. significantly less than 4

d. significantly less than 4.6

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The manager of a grocery store has taken a random sample of 100 customers. The average...
The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in the sample to check out was 3.1 minutes. The population standard deviation is known at 0.5 minutes. We want to test to determine whether or not the mean waiting time of all customers is significantly different than 3 minutes. Use α = 0.05. 14. The test statistic is a. 1.96 b. 1.64 c. 2.00 d. 0.056...
The manager of a grocery store has taken a random sample of 100 customers to determine...
The manager of a grocery store has taken a random sample of 100 customers to determine whether or not the mean waiting time of all customers is significantly more than 3 minutes. She observes that the average length of time it took the customers in the sample to check out was 3.1 minutes. The population standard deviation is known to be 0.5 minutes. USE INFORMATION TO ANSWER THE FOLLOWING: 1A. What is the appropriate test to use for this problem?...
The manager of a grocery store has taken a random sample of 100 customers. The average...
The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in the sample to check out was 3.1 minutes. The population standard deviation is known to be 0.5 minute. We want to test to determine whether or not the mean waiting time of all customers is significantly more than 3 minutes. The test statistic is _____. a. 1.64 b. 2.00 c. 1.96 d. .056
The manager of a grocery store has taken a random sample of 4 customers. The average...
The manager of a grocery store has taken a random sample of 4 customers. The average length of time it took the customers in the sample to check out was 6 minutes. The population standard deviation is known to be 0.1 minutes. We want to test to determine whether or not the mean waiting time of all customers is significantly more than 7 minutes. Use a significance level of (alpha = 0.01). Please show work.
The manager of a grocery store has taken a random sample of 100 customers. The average...
The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in the sample to check out was 4.9 minutes with a sample standard deviation of 0.5 minutes. Conduct a test to determine whether or not the mean waiting time of all customers is significantly more than 5 minutes. Use a significance level of α = 0.01.
The manager of a grocery store has taken a random sample of 196 customers.
The manager of a grocery store has taken a random sample of 196 customers. The average length of time it took these 196 customers to check out was 3 minutes. It is known that the standard deviation of the population of checkout times is 1 minute. The margin of error is 0.140. Find the 95% confidence interval for the true average checkout time (in minutes).A. 1 to 5B. 2.86 to 3.14    C. 2.883 to 3.117D. 2.990 to 3.010
A medium size grocery store runs its business 5 days a week for 8 hours each...
A medium size grocery store runs its business 5 days a week for 8 hours each day. The store has two counters and currently Emma and Sophia are working at the counters. The owner of the store wants to study the average time taken to serve a customer by Emma and Sophia. On a randomly selected day, he found that Emma served 50 customers at the counter with a mean time of 4 minutes and a standard deviation of 3...
A recent study by XYZ Research Agency of college students found that 33% of students drink...
A recent study by XYZ Research Agency of college students found that 33% of students drink energy drinks. A sample of 35 students found that 8 drink energy drinks. Assume alpha of .05 Find the following: Test Statistic Group of answer choices A. .23 B. .32 C. .45 D. .90 A recent study by XYZ Research Agency of college students found that 33% of students drink energy drinks. A sample of 35 students found that 8 drink energy drinks. Assume...
The mean amount purchased by a typical customer at Churchill's Grocery Store is $23.50 with a...
The mean amount purchased by a typical customer at Churchill's Grocery Store is $23.50 with a standard deviation of $6.00. Assume the distribution of amounts purchased follows the normal distribution. For a sample of 52 customers, answer the following questions. a. What is the likelihood the sample mean is at least $25.50? (Round z value to 2 decimal places and final answer to 4 decimal places.)   Probability b. What is the likelihood the sample mean is greater than $22.50 but...
The mean amount purchased by a typical customer at Churchill's Grocery Store is $23.50 with a...
The mean amount purchased by a typical customer at Churchill's Grocery Store is $23.50 with a standard deviation of $6.00. Assume the distribution of amounts purchased follows the normal distribution. For a sample of 52 customers, answer the following questions. a. What is the likelihood the sample mean is at least $25.50? (Round z value to 2 decimal places and final answer to 4 decimal places.)   Probability    b. What is the likelihood the sample mean is greater than $22.50...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT