The ages of all college students follow a normal distribution with a mean of 27 years and standard deviation of 4.4 years. Find the probability that the mean age for a random sample of 36 students would be:
Instructions:
Draw the normal curve and shade the area where applicable
Do not give calculator key strokes. (Give the formula used)
Circle your answer to the question.
This is a normal distribution question with
Sample size (n) = 36
Since we know that
a)
P(25.5 < x < 28.0)=?
This implies that
P(25.5 < x < 28.0) = P(-2.0455 < z < 1.3637) = P(Z < 1.3637) - P(Z < -2.0455)
P(25.5 < x < 28.0) = 0.9136689979678574 - 0.020402794603842655
b)
P(x < 25.5)=?
The z-score at x = 25.5 is,
z = -2.0455
This implies that
PS: you have to refer z score table to find the final probabilities.
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