A survey was conducted that asked 1013 people how many books they had read in the past year. Results indicated that x overbarxequals=10.9 books and sequals=16.6 books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval.
t critical value at 0.10 level with 1012 df = 1.646
90% confidence interval for is
- t * S / sqrt(n) < < + t * S / sqrt(n)
10.9 - 1.646 * 16.6 / sqrt(1013) < < 10.9 + 1.646 * 16.6 / sqrt(1013)
10.042 < < 11.758
90% CI is (10.042 , 11.758 )
Interpretation = We are 90% confident that the mean number of books people read is between 10.042 and 11.758.
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