Listed below are speeds (mi/h) measured from traffic on a busy highway. This simple random sample was obtained at 3:30 P.M. on a weekday. Use the sample data to construct a 98% confidence interval estimate of the population standard deviation. 64 62 62 56 62 53 60 59 60 69 61 68
From given sample,
Sample standard deviation S = 4.4586
Chi square critical values at 0.02 significance level with 11 df = 3.054 , 24.725
98% confidnce interval for is
Sqrt [ ( n - 1) S2 / U ] < < Sqrt [ ( n - 1) S2 / L ]
sqrt [ 11 * 4.45862 / 24.725 ] < < sqrt [ 11 * 4.45862 / 3.054 ]
2.97 < < 8.46
98% CI is ( 2.97 , 8.46)
Get Answers For Free
Most questions answered within 1 hours.