Question

The following data was obtained while watching the game Rock-Paper-Scissors. Each value represents the number of times a player used rock, paper, or scissors. Is there enough evidence to support that the moves (rock, paper, and scissors) are equally likely?  

Move	Frequency
Rock	59
Paper	56
Scissors	48

Answer 1

Total frequency = 59 + 56 + 48 = 163

As we are testing if each of them is equally likely, therefore the expected frequency for each of the above options is computed here as:
= 163/3

= 54.3333

The test statistic now is computed here as:

For n - 1 = 2 degrees of freedom, the p-value here is computed from the chi square distribution tables here as:

As the p-value here is very high, the test is not significant and we cannot reject the null hypothesis here. Therefore we dont have sufficient evidence here that the moves (rock, paper, and scissors) are equally likely