Let X be normally distributed with mean μ =
3,400 and standard deviation σ = 2,200. [You may
find it useful to reference the z
table.]
a. Find x such that P(X
≤ x) = 0.9382. (Round "z" value to 2
decimal places, and final answer to nearest whole
number.)
b. Find x such that P(X
> x) = 0.025. (Round "z" value to 2
decimal places, and final answer to nearest whole
number.)
c. Find x such that P(3,400 ≤
X ≤ x) = 0.1217. (Round
"z" value to 2 decimal places,
and final answer to nearest whole number.)
d. Find x such that P(X
≤ x) = 0.4840. (Round
"z" value to 2 decimal places,
and final answer to nearest whole number.)
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