From a sample of size 50, we have that Sxx=450 and Syy=800. Having tested the hypothesis that there is a negative relationship between two variables (i.e., H0:β1≤0), we obtain a p-value of 0.01186.
A. calculate the slope
Sample size,n = 50 Sxx= 450 (SSx)
SYY= 800( SSy)
Here, H0: β1≤0 Ha: β1>0 So, right tail t test is used . p-value is 0.01186 corresponding t statistic for n-2 = 50-2 = 48 degrees of freedom is 2.336 .
As t=β / SE (β1) = 2.336.
Thus β = 2.336 *(SE( β1)) -------(1)
Now,
where
Thus
Therefore using (1) equation
Slope = (2.336) (0.1925 )
= 0.44968
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