The following data are the monthly salaries y and the grade point averages x for students who obtained a bachelor's degree in business administration.
GPA | Monthly Salary ($) |
2.7 | 3,600 |
3.5 | 3,800 |
3.7 | 4,200 |
3.2 | 3,700 |
3.4 | 4,200 |
2.7 | 2,400 |
The estimated regression equation for these data is = -277.3 + 1,227.3x and MSE =217,386.
a. Develop a point estimate of the starting
salary for a student with a GPA of 3.0 (to 1 decimal).
$
b. Develop a 95% confidence interval for the
mean starting salary for all students with a 3.0 GPA (to 2
decimals).
$ ( , )
c. Develop a 95% prediction interval for Ryan
Dailey, a student with a GPA of 3.0 (to 2 decimals).
$ ( , )
a)
The point estimate of the starting salary for a student with a GPA of 3.0 is
Monthly Salary = -277.3 + 1227.3 * 3.0 = 3404.6
b)
Independent variable (x): GPA
Following table shows the calculations:
GPA, X | X^2 | |
2.7 | 7.29 | |
3.5 | 12.25 | |
3.7 | 13.69 | |
3.2 | 10.24 | |
3.4 | 11.56 | |
2.7 | 7.29 | |
Total | 19.2 | 62.32 |
Sample size: n=6
Now,
Since MSE = 217386 so
The critical value of t for 95% confidence interval with df = 4 is 2.776.
The 95% confidence interval for the mean starting salary for all students with a 3.0 GPA is
The required 95% confidence interval is (2808.49, 4000.71).
(c)
The 95% prediction interval for the mean starting salary for all students with a 3.0 GPA is
The required 95% prediction interval is (1979.62, 4829.58)
Get Answers For Free
Most questions answered within 1 hours.