Edith Educationer has a real problem with children’s television programs. She believes there are too many commercials in them. To study this, she collects a sample of 500 children’s programs (n = 500) and counts how many commercials are on during the program. The frequency count of programs with the number of commercials is found below:
Commercials, X |
8 |
9 |
10 |
11 |
12 |
Frequency |
50 |
75 |
150 |
125 |
100 |
P(X) |
Complete the table to produce the general discrete probability distribution. Use this probability distribution to answer questions a – h.
X | 8 | 9 | 10 | 11 | 12 |
Frequency | 50 | 75 | 150 | 125 | 100 |
Probability | 0.1 | 0.15 | 0.3 | 0.25 | 0.2 |
The above probabilities are computed by dividing the frequency by total number of students that is 500 in this case.
a) Most likely outcome is with highest probability that is 10 commercials
b) The average number of commercials is computed as:
Therefore
Therefore the mean is 10.3 commercials and standard deviation is 1.2288
c) P(X >= 10) = 0.3 + 0.25 + 0.2 = 0.75
d) P(X < 4) = 0
e) P(X = 12) = 0.2
f) P(X = 7) = 0
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