Question

We are interested in looking at the percentage of households that own dogs in the U.S. and England. We are given the following information:

	Number of people Surveyed	Number of people who own a dog
U.S.	700	294
England	850	391

The point estimate for the difference in proportions between people in the U.S. who own dogs and people in England who own dogs is:

	a.	0.04
	b.	0.0716
	c.	-0.04
	d.	-0.0716

We are interested in looking at the percentage of households that own dogs in the U.S. and England. We are given the following information:

	Number of people Surveyed	Number of people who own a dog
U.S.	700	294
England	850	391

What is the p-value for this test if we are interested in testing to see if there is simply a difference in the proportions of people who own dogs in the U.S. and England?

	a.	0.0571
	b.	.10 < p-value < .20
	c.	0.9429
	d.	0.1142

We are interested in comparing the average price of cars in 2015 and 2010. We are given the following data:

	2010	2015
Sample Mean	$29,217	$31,252
Sample Standard Deviation	$4,560	$3,942
Sample Size	30	22

Find the 95% confidence interval for the difference from 2015 to 2010.

	a.	(-341.145, 4411.14)
	b.	(-4411.14, 341.145)
	c.	(1998.45, 2071.55)
	d.	(-2071.55, 1998.45)

We are interested in comparing the average price of cars in 2015 and 2010. We are given the following data:

	2010	2015
Sample Mean	$29,217	$31,252
Sample Standard Deviation	$4,560	$3,942
Sample Size	30	22

The test statistic is:

	a.	t= -1.72
	b.	z= 1.72
	c.	t= 1.72
	d.	z= -1.72

We are interested in studying the difference in mile running times for beginners 30 days into training and then 90 days into training to see if they have made significant improvements. The following data is provided:

Runner	30 days	90 days
1	10.2	9.8
2	9.7	8.75
3	8.9	8.0
4	11.6	10.9
5	12.9	12.2

What is the average difference between 30 days and 90 days?

	a.	3.65
	b.	0.73
	c.	-0.73
	d.	0.59

We are interested in studying the difference in mile running times for beginners 30 days into training and then 90 days into training to see if they have made significant improvements. The following data is provided:

Runner	30 days	90 days
1	10.2	9.8
2	9.7	8.75
3	8.9	8.0
4	11.6	10.9
5	12.9	12.2

The test statistic is:

	a.	t=0.2168
	b.	z=7.5292
	c.	t= -7.5292
	d.	t= 7.5292

Answer 1

We are given that:

	Number of people Surveyed	Number of people who own a dog
U.S.	700	294
England	850	391

Proportion of people in the England who own dogs = 391/850 = 0.46 Proportion of people in the US who own dogs = 294/700 = 0.42

The difference in proportions between people in the US who own dogs and people in England who own dogs = 0.42 - 0.46 = -0.04

Option c.-0.04 is correct.

We are given that n₁ = 700, p₁= 294/700 = 0.42, n2 = 850, p2= 391/850 = 0.46

q = 1 -p= 0.5581

Test statistic is:

Z = (0.42 - 0.46)/0.0253 =- 1.58

you can use excel function ''2*NORMSDIST(-1.58) will get p-value 01142

Correct option is d.0.1142.

Hope this will helpful. Thanks and God Bless You:)