Question

The weight of a type of dog follows Normal distribution with mean of 44 pounds and standard deviation of 3 pounds.

1. What is the probability a dog of this type will weigh more than 100 pounds? (Show your work.)

2. What is the probability a dog of this type will weigh more than 10 pounds? (Show your work.)

Answer #1

1)

for normal distribution z score =(X-μ)/σx | |

here mean= μ= | 44 |

std deviation =σ= | 3.000 |

probability a dog of this type will weigh more than 100 pounds:=P(X>100)=P(Z>(100-44)/3)

=P(Z>18.67)=**0.0000** (as probability of having
a z score above 4 is almost negligible)

2)

probability a dog of this type will weigh more than 10 pounds=P(X>10)=P(Z>(10-44)/3)

=P(Z>-11.33)**=1.0000** (as probability below z
score -4 is almost negligible)

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