Question

The weight of a type of dog follows Normal distribution with mean of 44 pounds and standard deviation of 3 pounds.

1. What is the probability a dog of this type will weigh more than 100 pounds? (Show your work.)  

2. What is the probability a dog of this type will weigh more than 10 pounds? (Show your work.)

Answer 1

1)

for normal distribution z score =(X-μ)/σx
here mean=       μ=	44
std deviation   =σ=	3.000

probability a dog of this type will weigh more than 100 pounds:=P(X>100)=P(Z>(100-44)/3)

=P(Z>18.67)=0.0000 (as probability of having a z score above 4 is almost negligible)

2)

probability a dog of this type will weigh more than 10 pounds=P(X>10)=P(Z>(10-44)/3)

=P(Z>-11.33)=1.0000 (as probability below z score -4 is almost negligible)