Question

The National Student Loan Survey asked the student loan borrowers in their sample about attitudes toward debt. Below are some of the questions they asked, with the percent who responded in a particular way. Assume that the sample size is 1298 for all these questions. Compute a 95% confidence interval for each of the questions, and write a short report about what student loan borrowers think about their debt. (Round your answers to three decimal places.)

(a) "To what extent do you feel burdened by your student loan payments?" 57% said they felt burdened.

(____, ____)

(b) "If you could begin again, taking into account your current
experience, what would you borrow?" 54% said they would borrow
less.

(____, ____)

(c) "Since leaving school, my education loans have not caused me
more financial hardship than I had anticipated at the time I took
out the loans." 33.9% disagreed.

(____, ____)

(d) "Making loan payments is unpleasant but I know that the
benefits of education loans are worth it." 57.9%agreed.

(____, ____)

(e) "I am satisfied that the education I invested in with my
student loan(s) was worth the investment for career opportunities."
57.1% agreed.

(____, ____)

(f) "I am satisfied that the education I invested in with my
student loan(s) was worth the investment for personal growth."
71.9% agreed.

(____, ____) |

Conclusion

A. While many feel that loans are a burden and wish they had borrowed less, a minority are satisfied with their education.

B. While a minority feel that loans are a burden and wish they had borrowed more, a majority are satisfied with their education.

C. While many feel that loans are a burden and wish they had borrowed less, a majority are satisfied with their education.

D. While a minority feel that loans are a burden and wish they had borrowed more, a minority are satisfied with their education.

Answer #1

a)

z value at 95% = 1.96

CI = p +/- z *sqrt(p*(1-p)/n)

= 0.57 +/- 1.96*sqrt(0.57 *(1-0.57)/1298)

= (0.543,0.597)

b)

CI = p +/- z *sqrt(p*(1-p)/n)

= 0.54 +/- 1.96*sqrt(0.54 *(1-0.54)/1298)

= (0.513,0.567)

c)

CI = p +/- z *sqrt(p*(1-p)/n)

= 0.339 +/- 1.96*sqrt(0.339 *(1-0.339)/1298)

= (0.313,0.365)

d)

CI = p +/- z *sqrt(p*(1-p)/n)

= 0.579 +/- 1.96*sqrt(0.579 *(1-0.579)/1298)

= (0.552,0.606)

e)

CI = p +/- z *sqrt(p*(1-p)/n)

= 0.571 +/- 1.96*sqrt(0.571 *(1-0.571)/1298)

= (0.544,0.598)

f)

CI = p +/- z *sqrt(p*(1-p)/n)

= 0.719 +/- 1.96*sqrt(0.719 *(1-0.719)/1298)

= (0.694,0.743)

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