Question

1)

H0:p=0.54H0:p=0.54

H1:p<0.54H1:p<0.54

Your sample consists of 88 subjects, with 47 successes. Calculate
the test statistic, rounded to 2 decimal places

z=

2) A well-known brokerage firm executive claimed that
at least 43 % of investors are currently confident of meeting their
investment goals. An XYZ Investor Optimism Survey, conducted over a
two week period, found that out of 106 randomly selected people, 41
of them said they are confident of meeting their goals.

Suppose you are have the following null and alternative hypotheses
for a test you are running:

H0:p=0.43H0:p=0.43

Ha:p<0.43Ha:p<0.43

Calculate the test statistic, rounded to 3 decimal places

3)In a recent Super Bowl, a TV network predicted that 58 % of
the audience would express an interest in seeing one of its
forthcoming television shows. The network ran commercials for these
shows during the Super Bowl. The day after the Super Bowl, and
Advertising Group sampled 58 people who saw the commercials and
found that 34 of them said they would watch one of the television
shows.

Suppose you are have the following null and alternative hypotheses
for a test you are running:

H0:p=0.58H0:p=0.58

Ha:p>0.58Ha:p>0.58

Calculate the test statistic, rounded to 3 decimal places

Answer #1

1)

H0: p = 0.54

Ha: p < 0.54 (left tailed)

Sample proportion = 47 / 88 = 0.5341

Test statistics

z = - p / sqrt( p ( 1 -p ) / n)

= 0.5341 - 0.54 / sqrt( 0.54 * 0.46 / 88)

= -0.11

**Test statistics z = -0.11**

2)

H0: p = 0.43

Ha: p < 0.43 (left tailed)

Sample proportion = 41 / 106 = 0.3868

Test statistics

z = - p / sqrt( p ( 1 - p) / n)

= 0.3868 - 0.43 / sqrt( 0.43 * 0.57 / 106)

= -0.898

**Test statistics = -0.898**

3)

H0: p = 0.58

Ha: p > 0.58 (Right tailed)

Sample proportion = 34/58 = 0.5862

Test statistics

z = - p / sqrt( p( 1 - p) / n)

= 0.5862 - 0.58 / sqrt( 0.58 * 0.42 / 58)

= 0.096

**Test statistics z = 0.096**

In a recent Super Bowl, a TV network predicted that 47 % of the
audience would express an interest in seeing one of its forthcoming
television shows. The network ran commercials for these shows
during the Super Bowl. The day after the Super Bowl, and
Advertising Group sampled 103 people who saw the commercials and
found that 49 of them said they would watch one of the television
shows.
Suppose you are have the following null and alternative hypotheses
for...

In a recent Super Bowl, a TV network predicted that 33 % of the
audience would express an interest in seeing one of its forthcoming
television shows. The network ran commercials for these shows
during the Super Bowl. The day after the Super Bowl, and
Advertising Group sampled 150 people who saw the commercials and
found that 42 of them said they would watch one of the television
shows.
Suppose you are have the following null and alternative hypotheses
for...

In a recent Super Bowl, a TV network predicted that 65 % of the
audience would express an interest in seeing one of its forthcoming
television shows. The network ran commercials for these shows
during the Super Bowl. The day after the Super Bowl, and
Advertising Group sampled 71 people who saw the commercials and
found that 48 of them said they would watch one of the television
shows.
Suppose you are have the following null and alternative hypotheses
for...

A) In a recent Super Bowl, a TV network predicted that 38 % of
the audience would express an interest in seeing one of its
forthcoming television shows. The network ran commercials for these
shows during the Super Bowl. The day after the Super Bowl, and
Advertising Group sampled 89 people who saw the commercials and
found that 36 of them said they would watch one of the television
shows.
Suppose you are have the following null and alternative hypotheses...

In a recent Super Bowl, a TV network predicted that 37% of the
audience would express an interest in seeing one of the forthcoming
television shows. The network ran commercials for these shows
during the Super Bowl. The day after the Super Bowl and Advertising
Group sampled 118 people who saw the commercials and found that 41
of them said they would watch one of the television shows.
Suppose you are have the following null and alternative
hypotheses for a...

In a recent Super Bowl, a TV network predicted that 46 % of the
audience would express an interest in seeing one of its forthcoming
television shows. The network ran commercials for these shows
during the Super Bowl. The day after the Super Bowl, and
Advertising Group sampled 101 people who saw the commercials and
found that 41 of them said they would watch one of the television
shows.
Suppose you are have the following null and alternative
hypotheses for...

Testing:
H0:p=0.81H0:p=0.81
H1:p≠0.81H1:p≠0.81
Your sample consists of 115 subjects, with 88 successes. Calculate
the test statistic, rounded to 2 decimal places
z=____

Testing:
H0:p=0.5369H0
H1:p≠0.5369
Your sample consists of 93 subjects, with 49 successes. Calculate
the test statistic, rounded to 2 decimal places
z=

H0:p=0.69H0:p=0.69
H1:p<0.69H1:p<0.69
Your sample consists of 129 subjects, with 95 successes. Calculate
the test statistic, rounded to 2 decimal places
z=

A well-known brokerage firm executive claimed that at least 32 %
of investors are currently confident of meeting their investment
goals. An XYZ Investor Optimism Survey, conducted over a two week
period, found that out of 107 randomly selected people, 40 of them
said they are confident of meeting their goals.
Suppose you are have the following null and alternative hypotheses
for a test you are running:
H0:p=0.32
Ha:p<0.32
Calculate the test statistic, rounded to 3 decimal places
z=

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