Question

Body weights were measured for the herbivorous beetle Gonioctena quinquepunctata. The n1 = 24 females had...

Body weights were measured for the herbivorous beetle Gonioctena quinquepunctata. The n1 = 24 females had a mean body weight of 1 x = 15.5 mg and a standard deviation of s1 = 2.1 mg. The n2 = 18 males mean body weight of 2 x = 14.2 mg with a standard deviation of s2 = 2.5 mg. Test the hypothesis of no difference in the mean body weights of females and males at the 5% level of significance.

Homework Answers

Answer #1

To Test :-

H0 :-  

H1 :-  

Test Statistic :-


t = 1.7841


Test Criteria :-
Reject null hypothesis if


DF = 32


Result :- Fail to Reject Null Hypothesis

Decision based on P value
P - value = P ( t > 1.7841 ) = 0.0839
Reject null hypothesis if P value < level of significance
P - value = 0.0839 > 0.05 ,hence we fail to reject null hypothesis
Conclusion :- We Accept H0

There is sufficient evidence to support the claim that no difference in the mean body weights of females and males at the 5% level of significance.

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