Body weights were measured for the herbivorous beetle Gonioctena quinquepunctata. The n1 = 24 females had a mean body weight of 1 x = 15.5 mg and a standard deviation of s1 = 2.1 mg. The n2 = 18 males mean body weight of 2 x = 14.2 mg with a standard deviation of s2 = 2.5 mg. Test the hypothesis of no difference in the mean body weights of females and males at the 5% level of significance.
To Test :-
H0 :-
H1 :-
Test Statistic :-
t = 1.7841
Test Criteria :-
Reject null hypothesis if
DF = 32
Result :- Fail to Reject Null Hypothesis
Decision based on P value
P - value = P ( t > 1.7841 ) = 0.0839
Reject null hypothesis if P value <
level of significance
P - value = 0.0839 > 0.05 ,hence we fail to reject null
hypothesis
Conclusion :- We Accept H0
There is sufficient evidence to support the claim that no difference in the mean body weights of females and males at the 5% level of significance.
Get Answers For Free
Most questions answered within 1 hours.