Using this data, Implement the following hypothesis test:
H0: μ = 7.53
H1: μ ≠ 7.53
DATA:
4.83
1.18
3.43
-0.36
4.01
7.35
14.63
8.86
6.25
6.47
8.84
5.8
2.6
10.44
A) Compute x
B) Compute S
C) Compute t0
D) Find tα/2,n-1 for a confidence levelof α = 0.05
E) Based on t0 andtα/2,n-1, would you reject H0?
F) What is the P-value for your t0?
Solution:
a) For computing we have to first input all data in excel and use command ,
=AVERAGE( data_range )
Mean = = 6.02
B) For standard deviation use command in excel,
=STDEV( data_range )
S = 3.92
C)
The t-statistic is computed as follows:
−1.441
D) Based on the information provided, the significance level is α = 0.05, and the critical value for a two-tailed test is tc =2.16.
E) Since it is observed that |t| = 1.441 ≤ tc = 2.16, it is then concluded that the null hypothesis is not rejected
F) The p-value is p = 0.1732 ...........Using excel, =TDIST(1.44,13,2)
Done
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