Question

Find the critical value, tα/2, for confidence level = 0.90 and n = 6. Round to...

Find the critical value, tα/2, for confidence level = 0.90 and n = 6. Round to 3 decimal places.

Homework Answers

Answer #1

α = 1 - 0.90

= 0.10

α/2 = 0.05

degree of freedom= n-1 = 6-1 = 5

t0.05 (degree of freedom=5) = 2.5710 {from table}

(please upvote)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Use technology to find the critical value tα/2 that corresponds to a confidence level of 80%...
Use technology to find the critical value tα/2 that corresponds to a confidence level of 80% from a sample of size n = 32. Please break it down for me into steps - I am having a tough time grasping the concepts and want to understand. Thanks!!
1.Find the critical value tα/2 needed to construct a confidence interval of the given level with  given...
1.Find the critical value tα/2 needed to construct a confidence interval of the given level with  given sample size. Level 90%, sample size 21 Group of answer choices 1.725 1.325 1.721 1.645 2.   Find the probability P(-0.62 < z < -0.01) using the standard normal distribution. Group of answer choices 0.2284 0.3584 0.7716 0.1900
Find the critical value tα to be used for a confidence interval for the mean of...
Find the critical value tα to be used for a confidence interval for the mean of the population in each of the following situations. (a) a 95% confidence interval based on n = 12 observations (b) a 90% confidence interval from an SRS of 22 observations (c) an 80% confidence interval from a sample of size 40
For a confidence level of 85%, find the critical value to 2 decimal places. For a...
For a confidence level of 85%, find the critical value to 2 decimal places. For a confidence level of 85%, find the critical value to 2 decimal places. z =
Use the Student's t distribution to find tc for a 0.90 confidence level when the sample...
Use the Student's t distribution to find tc for a 0.90 confidence level when the sample is 6. (Round your answer to three decimal places.)
4. Find the critical value Z a/2 that corresponds to the given confidence level. 81​% Z...
4. Find the critical value Z a/2 that corresponds to the given confidence level. 81​% Z a/2=____ (Round to two decimal places as​ needed.) 5. Express the confidence interval 0.555<p<0.777 in the form ˆp ± E ˆp ± E=____±____ 6. Express the confidence interval (0.073,0.117) in the form of ˆp- E< p < ˆp + E ____<p<____ ​(Type integers or​ decimals.)
Find the critical value t a/2 needed to construct a confidence interval of the given level...
Find the critical value t a/2 needed to construct a confidence interval of the given level with th sample size. Round the amswers to theee decimal places. For level 95% and sample size 11? For level 98% and sample size 26? For level 99% and sampke size 12?
1) Find the critical value t (a/2) needed to construct a confidence interval of the given...
1) Find the critical value t (a/2) needed to construct a confidence interval of the given level with the given sample size. Round the answers to three decimal places a) 98% sample size 11 critical value- b) for level 95% and sample size 25 critical value- c)for level 99% and sample size 14 2) a sample of size n equals 45 has a sample mean X equals 56.9 and sample standard deviation s equals 9.4. construct a 99% confidence interval...
Critical values for quick reference during this activity. Confidence level Critical value 0.90 z∗=1.645 0.95 z∗=1.960...
Critical values for quick reference during this activity. Confidence level Critical value 0.90 z∗=1.645 0.95 z∗=1.960 0.99 z∗=2.576 Jump to level 1 In a poll of 1000 randomly selected voters in a local election, 728 voters were against school bond measures. What is the sample proportion p^? (Should be a decimal answer) What is the margin of error m for the 95% confidence level? (Should be a decimal answer)
Use the Student's t distribution to find tc for a 0.90 confidence level when the sample...
Use the Student's t distribution to find tc for a 0.90 confidence level when the sample is 20. (Round your answer to three decimal places.)