A novelty die with six sides is printed with the numbers 1, 2, 3, 4, 8, 16. (a) If the die is rolled once what is the probability of geting an odd number? (b) If the die is rolled twice and the numbers for each roll added together, what is the probability of getting an odd sum?
Solution:-
a.) Number of total odd outcomes:{1,2,3}=3
probability of getting an odd number=3/6
=0.5
b.) Total possible outcomes when the die is rolled twice:
{(1,1),(1,2),(1,3),(1,4),(1,8),(1,16),(2,1),(2,2),(2,3),(2,4),(2,8),(2,16),(3,1),(3,2),(3,3),(3,4),(3,8),(3,16),(4,1),(4,2),(4,3),(4,4),(4,8),(4,16),(8,1),(8,2),(8,3),(8,4),(8,8),(8,16),(16,1),(16,2),(16,3),(16,4),(16,8),(16,16)}
when added Together
s={2,3,4,5,9,17,3,4,5,6,10,18,4,5,6,7, 11,19,5,6,7,8,12,20,9,10,11,12,16,24,17,18,19,20,24,32}
Number of events of added together is odds=16
probability(odd sum)=16/36
=0.4444
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