Question

in order to determine the average price of hotel rooms is Atlanta, a sample of 64...

in order to determine the average price of hotel rooms is Atlanta, a sample of 64 hotels was selected. it was determined that the average price of the rooms in the sample was $ 112. the population standard deviation is known to be $16. It was determined that the average price of the rooms in the sample was $108.50

1. at 90% confidence using the p-value approach, test the hypothesis. what is your conclusion and why?

2. repeat the hypothesis testing with the critical value approach. What is your conclusion any why?

Homework Answers

Answer #1

Given that, sample size ( n ) = 64

sample mean = $ 112

population standard deviation = $ 16

The null and the alternative hypotheses are,

Test statistic is,

1) confidence level = 0.90

=> significance level = 1 - 0.90 = 0.10

p-value = 2 * P(Z > 1.75) = 2 * 0.0401 = 0.0802

=> p-value = 0.0802

Since, p-value = 0.0802 <

we reject the null hypothesis ( H0).

2) critical values at are, Z* = ± 1.645

Here, test statistic = 1.75 > 1.645

=> we reject the null hypothesis (H0).

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In order to determine the average price of hotel rooms in Atlanta, a sample of 64...
In order to determine the average price of hotel rooms in Atlanta, a sample of 64 hotels was selected.  It was determined that the average price of the rooms in the sample was $108.50. Let the population standard deviation of room price be $16. a. Formulate the hypotheses to determine whether or not the average room price is significantly different from $110.             b.   Compute the test statistic.             c.    At 99% confidence using the p-value approach, test the hypotheses.  
1. In order to determine the average price of hotel rooms in Atlanta. Using a 0.1...
1. In order to determine the average price of hotel rooms in Atlanta. Using a 0.1 level of significance, we would like to test whether or not the average room price is significantly different from $110. The population standard deviation is known to be $16. A sample of 64 hotels was selected. The test statistic (z) is calculated and it is 1.36. We conclude that the average price of hotel rooms in Atlanta is NOT significantly different from $110. (Enter...
In order to determine if the average prices of hotel rooms are different between City A...
In order to determine if the average prices of hotel rooms are different between City A and City B, a sample from each city was randomly selected. The table below summarizes the data provided by these samples: City A City B Sample mean $81.97 $74.40 Sample standard deviation $10.63 $9.58 Sample size 40 45 Conduct the appropriate statistical test to determine if the average price of hotel rooms differ between City A and City B (alpha = .05, d.f. =...
The average cost of a hotel room is said to be $170 per night. To determine...
The average cost of a hotel room is said to be $170 per night. To determine if this is true, a random sample of 50 hotels is taken and resulted in a mean of $172.50 and an S of $15.40. At 98% confidence level, the positive value of the critical value is______ (Hint use Excel T.INV function)
Question 7     You work for a hotel chain. You boss wants to know what the...
Question 7     You work for a hotel chain. You boss wants to know what the mean price for a comparable hotel room in Kansas City to help her determine what she should charge for your chain's rooms. You sample 101 random hotels similar to your own and get the daily cost of a room for each. You compute a mean cost of $96.50. The standard deviation of your sample is $19.50. What is the 95% confidence interval for the...
A sample of 64 account balances from a credit company showed an average daily balance of...
A sample of 64 account balances from a credit company showed an average daily balance of $1,040. The standard deviation of the population is known to be $200. We are interested in determining if the mean of all account balances (i.e., population mean) is significantly different from $1,000. a. Develop the appropriate hypotheses for this problem. b. Compute the test statistic. c. Compute the p-value. d. Using the p-value approach at 95% confidence, test the above hypotheses. e. Using the...
Austin Houston Sample Size 15 12 Sample Mean 188.2000 155.3333 Sample Standard Deviation 41.4319 28.4328 df...
Austin Houston Sample Size 15 12 Sample Mean 188.2000 155.3333 Sample Standard Deviation 41.4319 28.4328 df 25 Pooled Sample Standard Deviation 36.2905 Confidence Interval (in terms of Austin - Houston) Confidence Coefficient 0.90 Lower Limit 8.8583 Upper Limit 56.8750 Hypothesis Test (in terms of Austin - Houston) Hypothesized Value 5 Test Statistic p-value (Lower Tail) p-value (Upper Tail) 0.0292 p-value (Two Tail) Expedia is interested in looking at the difference in the average price of a hotel room in Austin...
A researcher wished to compare the average daily hotel room rates between San Francisco and Los...
A researcher wished to compare the average daily hotel room rates between San Francisco and Los Angeles. The researcher obtained an SRS of 15 hotels in downtown San Francisco and found the sample mean x1=$156 , with a standard deviation s1= $15 . The researcher also obtained an independent SRS of 10 hotels in downtown Los Angeles and found the sample mean x2= $143, with a standard deviation s2=$10. Let 1 and 2 represent the mean cost of the populations...
Danvers-Hilton Resort Hotel states that its weekend guest bill has been on average $1,200 for the...
Danvers-Hilton Resort Hotel states that its weekend guest bill has been on average $1,200 for the last 5 years with a standard deviation of $200. The CEO believes that this year the value of weekend bills has changed and he hires you to statistically test whether this is true. You collect a sample of 100 weekend bills finding an average amount of $1,230. You state the following hypothesis: H0 : µ = 1200 Ha : µ ≠ 1200 Conduct a...
The average gasoline price at Chevron was $3.12 per gallon last month. Due to the recent...
The average gasoline price at Chevron was $3.12 per gallon last month. Due to the recent nation-wide gas price drop, the chief marketing officer of Chevron believes that there has been a significant reduction in the average gas price. In order to test his belief, he randomly selected a sample of 36 of Chevron gas stations and found the average gas price of these stations was $3.06. Assume that the population standard deviation of the population is $0.12, and the...