Fowle Marketing Research, Inc., bases charges to a client on the assumption that telephone surveys can be completed in a mean time of 15 minutes or less. If a longer mean survey time is necessary, a premium rate is charged. Suppose a sample of 35 surveys produces the data in the Microsoft Excel Online file below. Use a known σ = 3.5 minutes. Is the premium rate justified?
Call Time (minutes) |
20.3 |
13.7 |
16.2 |
18.1 |
13.8 |
17.3 |
14.6 |
17.4 |
18.5 |
10.5 |
15.1 |
16.6 |
17 |
14.5 |
20 |
11.3 |
16.3 |
20.5 |
21.7 |
16 |
12.2 |
18.5 |
25.9 |
14.5 |
21.6 |
15.6 |
15.9 |
14.7 |
17.6 |
18 |
16.7 |
11.6 |
16.8 |
13 |
13.2 |
a. Formulate the null and alternative hypotheses for this application.
H0: μ ? ___
Ha: μ ? ___
b.Compute the value of the test statistic (to 2 decimals).
c.What is the p-value (to 4 decimals)?
d.Using ? = .01, is a premium rate justified for this client?
yes or no?
First enter Data into EXCEL
We have to find the sample mean.
Excel command is =AVERAGE(Select data)
sample mean = 16.43
n = 35
claim :premium rate justified for this client
a)
Null and alternative hypothesis is
Level of significance = 0.01
b)
Here population standard deviation is known so we use z-test statistic.
Test statistic is
Degrees of freedom = n - 1 = 35-1=34
c)
P-value =0.00776. ( using z table)
The P-Value is 0 .0078
P-value , Reject H0
d)
conclusion :Yes Using ? = .01, premium rate justified for this client.
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