Beer bottles are filled so that they contain an average of 330 ml of beer in each bottle. Suppose that the amount of beer in a bottle is normally distributed with a standard deviation of 4 ml.
Solution :
(a)
P(x < 325) = P[(x -
) /
< (325 - 330) / 4]
= P(z < -1.25)
= 0.1056
(b)
=
/
n = 4 /
6
P(
< 328) = P((
-
) /
< (328 - 330) / 4 /
6 )
= P(z < 1.225)
= 0.1103
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