Question

Erythromycin is a drug that has been proposed to possibly lower
the risk of premature delivery. A related area of interest is its
association with the incidence of side effects during pregnancy.
Assume that 30% of all pregnant women complain of nausea between
the 24th and 28th week of pregnancy. Furthermore, suppose that of
178 women who are taking erythromycin regularly during this period,
63 complain of nausea. Find the p-value for testing the
hypothesis that incidence rate of nausea for the erythromycin group
is greater than for a typical pregnant woman. |

Answer #1

Solution :

Given that,

= 0.30

1 - = 0.70

n = 178

x = 63

Point estimate = sample proportion = = x / n = 0.354

This a right (One) tailed test.

The null and alternative hypothesis is,

Ho: p = 0.30

Ha: p 0.30

Test statistics

z = ( - ) / *(1-) / n

= ( 0.354 - 0.30) / (0.30*0.70) /178

= 1.57

P-value = P(Z>z)

= 1 - P(Z <z )

= 1- P(Z < 1.57)

= 1 - 0.9418

= 0.0582

**The p-value is p = 0.0582**

rythromycin is a drug that has been proposed to possibly lower
the risk of premature delivery. A related area of interest is its
association with the incidence of side effects during pregnancy.
Assume that 30% of all pregnant women complain of nausea between
the 24th and 28th week of pregnancy. Furthermore, suppose that of
199 women who are taking erythromycin regularly during this period,
70 complain of nausea. The p-value for testing the
hypothesis that incidence rate of nausea for...

Erythromycin is used to increase the risk of nausea during
pregnancy. 30% of all pregnant women complain of nausea between
weeks 24 and 28 of pregnancy. A study is conducted of 200 pregnant
women who are taking erythromycin during pregnancy between the 24th
and 28th week of pregnancy and 110 complain of nausea during that
time period. determine the incidence of nausea is different among
women taking erythromycin compared to typical pregnant women.

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