Question

Compute using ti84 calculator: The number of flaws in a given area of aluminum foil follows a Poisson distribution with a mean of 3 per square meter. Suppose you need a 2 square meter sheet of aluminum foil to "calibrate the radar" of the mega-yacht Eros. Compute to the nearest 0.0001: A) The probability of exactly 6 flaws in this sheet. B) The probability of less than 3 flaws in this sheet.

Answer 1

We have :

For this problem :

A)

Probability of exactly 6 flaws in this sheet = P(X=6)

Using Ti-84 calculator function "poissonpdf()" , we find the above probability as :

P(X=6) = Poissonpdf( X = 6 , Mean = 6 ) = 0.1606

So,

Probability of exactly 6 flaws in this sheet = 0.1606

B)

Probability of less than 3 flaws in this sheet = P(X<3 )

So, using Ti-84 calculator function "poissonpdf()" , we find the above probability as :

P(X 2) = Poissonpdf( X = 2 , Mean = 6 ) = 0.0620

So,

Probability of less than 3 flaws in this sheet = 0.0620