Assume that the differences are normally distributed. Complete parts (a) through (d) below.
Observation |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
|
---|---|---|---|---|---|---|---|---|---|
Upper X Subscript iXi |
48.948.9 |
50.050.0 |
45.645.6 |
46.146.1 |
52.552.5 |
44.444.4 |
45.145.1 |
45.245.2 |
|
Upper Y Subscript iYi |
52.552.5 |
50.850.8 |
50.250.2 |
51.451.4 |
52.852.8 |
45.745.7 |
48.848.8 |
47.947.9 |
(a) Determine
d Subscript i Baseline equals Upper X Subscript i Baseline minus Upper Y Subscript idi=Xi−Yi
for each pair of data.
Observation |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
---|---|---|---|---|---|---|---|---|
di |
nothing |
nothing |
nothing |
nothing |
nothing |
nothing |
nothing |
nothing |
(b) Compute
d overbard
and
s Subscript dsd.
(c) Test if
mu Subscript dμdless than<0
at the
alphaαequals=0.05
level of significance.
(Type integers or decimals.)
a)
diff:(d)=x1-x2 |
-3.6 |
-45.8 |
-4.6 |
-5.3 |
-0.3 |
-1.3 |
-3.7 |
-2.7 |
b)
dbar = -8.413 (please take care of number of decimals as required in question)
sd =13.1961
test statistic = | (d̅-μd)/Se = | -1.566 |
p value | = | 0.0807 |
fail to reject the null
Get Answers For Free
Most questions answered within 1 hours.