0.25 1.63 2.22 2.46 2.42 2.45 1.64 2.10 1.69 2.34 1.34 2.34 0.99 3.03 4.16 0.00 3.12
3.04 2.40 1.49
(d) The R code and the results are given below:
> x=c(0.25, 1.63, 2.22, 2.46, 2.42, 2.45, 1.64,
2.10, 1.69, 2.34, 1.34, 2.34, 0.99, 3.03, 4.16, 0.00, 3.12, 3.04,
2.40, 1.49)
> t.test(x,mu=0,)
One Sample t-test
data: x
t = 9.397, df = 19, p-value = 1.419e-08
alternative hypothesis: true mean is not equal to 0
95 percent confidence interval:
1.597672 2.513328
sample estimates:
mean of x
2.0555
(e) From the R code result above, we conclude that since
p-value is less than 0.05, we reject the null hypothesis. We
further conclude that there is enough evidence to suggest that the
mass of the spiny-backed bacteria is significantly different than
zero.
Get Answers For Free
Most questions answered within 1 hours.