1. For a standard normal distribution, given:
P(z < c) = 0.7232
Find c. (WHERE is this on the z score table and can I figure in
excel/sheets?)
2. For a standard normal distribution, find:
P(z > c) = 0.0912
Find c.
3. About___ % of the area under the curve of the standard normal distribution is between z=−2.837z=-2.837 and z=2.837z=2.837 (or within 2.837 standard deviations of the mean). (HOW- preferably through technology/excel/sheets)
4. About___ % of the area under the curve of the standard normal distribution is outside the interval z=[−0.71,0.71]z=[-0.71,0.71] (or beyond 0.71 standard deviations of the mean).
5. Suppose your manager indicates that for a normally
distributed data set you are analyzing, your company wants data
points between z=−1.5z=-1.5 and z=1.5z=1.5standard deviations of
the mean (or within 1.5 standard deviations of the mean). What
percent of the data points will fall in that range?
Answer:___ percent (Enter a number between 0 and 100, not 0 and 1
and round to 2 decimal places)
Thank you for explaining how and using current technology/quickest way (avpid tables and formulas if possibly) Thanks a million!!
Solution :
Using standard normal table,
1)
P(z < c) = 0.7232
To see the probability 0.7232 in the standard normal table the cumulative z value is 0.59 .
P(z < 0.59) = 0.7232
c = 0.59
2)
P(z > c) = 0.0912
1 - P(z < c) = 0.0912
P(z < c) = 1 - 0.0912 = 0.9088
P(z < 1.33) = 0.9088
c = 1.33
3)
P(-2.837 < z < 2.837) = P(z < 2.837 ) - P(z < -2.837) = 0.9977 - 0.0023 = 0.9954
About 99.54% of the area under the curve of the standard normal distribution is between
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