Roll a 20-sided die 10 times. Find the probability of getting: i. At least one six ii. At least one five and one six iii. 3 sixes given that no number larger than 12 appears iv. 3 sixes, 2 twelves, 4 twos, and 1 eight v. 1 triple, 3 doubles, and 1 single
the probability of getting a 6 in a roll of 20 sided die is
i) If the die is rolled 10 times, the probability of getting At least one six =1- the probability of getting no six
ii) the probability of getting At least one five and one six =1- the probability of getting no six and no 5
iii) A = getting 3 sixes
B = no number larger than 12 appears
iv) Total number of ways to get 3 sixes, 2 twelves, 4 twos, and 1 eight =
probability of getting six, twelve,two, 1 is same for a toss: p=0.5
hence the required probability is
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