Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.)
μ = 106; σ = 10
P(x ≥ 120) =
Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.)
μ = 110; σ = 13
P(x ≥ 90) =
Solution :
Given that ,
mean =
= 106
standard deviation =
=10
P(x ≥ 120) = 1 - p( x< 120)
=1- p P[(x -
) /
< (120 - 106) /10 ]
=1- P(z < 1.4)
Using z table,
= 1 -0.9192
answer =0.0808
Solution :
Given that ,
mean =
= 110
standard deviation =
=13
P(x ≥ 90) = 1 - p( x< 90)
=1- p P[(x -
) /
< (90 - 110) /13 ]
=1- P(z < -1.54)
Using z table,
= 1 -0.0618
answer =0.9382
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