Question

According to the South Dakota Department of Health, the number of hours of TV viewing per week is higher among adult women than adult men. A recent study showed women spent an average of 30 hours per week watching TV, and men, 22 hours per week. Assume that the distribution of hours watched follows the normal distribution for both groups, and that the standard deviation among the women is 4.1 hours and is 5.0 hours for the men. What percent of the women watch TV less than 35 hours per week? (Round your z-score computation and final answer to 2 decimal places.) What percent of the men watch TV more than 18 hours per week? (Round your z-score computation and final answer to 2 decimal places.) How many hours of TV do the four percent of women who watch the most TV per week watch? Find the comparable value for the men. (Round your answers to 3 decimal places.)

Answer 1

Solution:-

a) The percent of the women watch TV less than 35 hours per week is 0.889.

Mean = 30, S.D = 4.1

By applying normal distruibution:-

z = 1.22

P(z < 1.22) = 0.889.

b) The percent of the men watch TV more than 18 hours per week is 0.788.

Mean = 22, S.D = 5.0

By applying normal distruibution:-

z = - 0.80

P(z > - 0.80) = 0.788

c) The four percent of women who watch the most TV per week watch is 37.18.

p-value for the top 4% = 0.96

z-score for the p-value = 1.751

By applying normal distruibution:-

x = 37.18

d) The comparable value for the men is 30.755.

p-value for the top 4% = 0.96

z-score for the p-value = 1.751

By applying normal distruibution:-

x = 30.755