Question

The Wall Street Journal reported that 33% of taxpayers with adjusted gross incomes between $30,000 and...

The Wall Street Journal reported that 33% of taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return. The mean amount of deductions for this population of taxpayers was $16,028 . Assume that the standard deviation is=$2997 . Use z-table.

a. What is the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $209 of the population mean for each of the following sample sizes:30 ,50 ,100 ,400 and ? Round your answers to four decimals.

n=30 _____

n=50 ______

n=100_____

n=400_____


b. What is the advantage of a larger sample size when attempting to estimate the population mean? Round your answers to four decimals.

A larger sample - Select your answer -(increases/decreases)Item 5 the probability that the sample mean will be within a specified distance of the population mean. In the automobile insurance example, the probability of being within +/- 209 of  ranges from______ for a sample of size 30 to_______ for a sample of size 400 .

Homework Answers

Answer #1

a)

for n=30,

for normal distribution z score =(X-μ)/σx
here mean=       μ= 16028
std deviation   =σ= 2997.0000
sample size       =n= 30
std error=σ=σ/√n= 547.1748
probability = P(15819<X<16237) = P(-0.38<Z<0.38)= 0.6480-0.3520= 0.2960

as above:

n probability
30 0.2960
50 0.3758
100 0.5160
400 0.8354

b)

A larger sample increases the probability that the sample mean will be within a specified distance of the population mean. In the automobile insurance  example, the probability of being within +/- 209 of  ranges from 0.2960 for a sample of size 30 to 0.8354 for a sample of size 400 .

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